X IPS 2//Restoe Agung Anak Permana//Remed PTS 📝📝
Bu, saya minta maaf bu. Saya tidak mengisi semua. Alasannya karena saya tidak paham dengan materi yang ada di semester 1 ini bu. Sekali lagi saya mohon maaf bu 🙏 1. |2x-7| = 3 2x -7 = 3 2x = 3 + 7 = 10 x = 10/2 = 5 -2x + 7 = 3 -2x = 3 - 7 = -4 2x = 4 x = 4/2 = 2 Hp = { 2, 5 } 2. |2x - 1| = |x + 4| |2x - 1| ² = |x + 4|² (2x - 1)² = (x + 4)² (2x - 1)² - (x + 4)² = 0 [(2x - 1 - x - 4)(2x - 1 + x + 4)] = 0 (x - 5)(3x + 3) = 0 x - 5 = 0 atau 3x + 3 = 0 x = 5 atau x = -1 Hp = {-1, 5} 3. |(x + 7) / (2x - 1)| = 2 |(x + 7)| 2 ––——— = – |(2x - 1)| 1 |x + 7| = |4x - 2| (x + 7)² = (4x - 2)² (x + 7)² - (4x - 2)² = 0 [(x + 7 - 4x + 2)(x + 7 + 4x - 2)] (-3x + 9)(5x + 5) = 0 -3x + 9 = 0 atau 5x + 5 = 0 x = 3 atau x = -1 Hp = {-1, 3} 4. 2(-2x - 2) - 3 = 13 -4x - 4 - 3 = 13 -4x = 13 + 4 + 3 = 20 x = -5 2(2x + 2) - 3 = 13 4x + 4 - 3 = 13 4x = 13 - 4 + 3 = 12 x = 3 Hp = {3, -5} 5. |4x + 2| ≥ 6 4x + 2 ≥ 6 atau 4x + 2 ≤ -6 4x ≥ 6 ...